Linear Algebra Examples

c = \frac{5}{9} \cdot (f - 32)

$c = \frac{5}{9} \cdot (f - 32)$

Step 1

Simplify

\frac{5}{9} \cdot (f - 32)

$\frac{5}{9} \cdot (f - 32)$ .

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Step 1.1

Apply the distributive property.

c = \frac{5}{9} f + \frac{5}{9} \cdot - 32

$c = \frac{5}{9} f + \frac{5}{9} \cdot - 32$

Step 1.2

Combine

\frac{5}{9}

$\frac{5}{9}$ and

f

$f$ .

c = \frac{5 f}{9} + \frac{5}{9} \cdot - 32

$c = \frac{5 f}{9} + \frac{5}{9} \cdot - 32$

Step 1.3

Multiply

\frac{5}{9} \cdot - 32

$\frac{5}{9} \cdot - 32$ .

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Step 1.3.1

Combine

\frac{5}{9}

$\frac{5}{9}$ and

- 32

$- 32$ .

c = \frac{5 f}{9} + \frac{5 \cdot - 32}{9}

$c = \frac{5 f}{9} + \frac{5 \cdot - 32}{9}$

Step 1.3.2

Multiply

5

$5$ by

- 32

$- 32$ .

c = \frac{5 f}{9} + \frac{- 160}{9}

$c = \frac{5 f}{9} + \frac{- 160}{9}$

c = \frac{5 f}{9} + \frac{- 160}{9}

$c = \frac{5 f}{9} + \frac{- 160}{9}$

Step 1.4

Move the negative in front of the fraction.

c = \frac{5 f}{9} - \frac{160}{9}

$c = \frac{5 f}{9} - \frac{160}{9}$

c = \frac{5 f}{9} - \frac{160}{9}

$c = \frac{5 f}{9} - \frac{160}{9}$

Step 2

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

(- \infty, \infty)

$(- \infty, \infty)$

Set-Builder Notation:

${x | x \in ℝ}$

Step 3

$c = \frac{5}{9} \cdot (f - 32)$

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